This is the solution to the additional puzzle I posted in Senket Puzzle of the Week #3.
I created this modified puzzle in reaction to Herman’s solution to the third puzzle of the week. The solution I had come up with involved jumping to the right four points, then putting a post midway between those two. Herman’s solution was better. So I tried again with this puzzle., since I like the move I came up with. Here’s my solution. Again, Red 1 starts by threatening to take 1 square immediately. Blue 2 cuts that off. Then the move I like: Red 3 jumps four points to the right, threatening to make territory at 4. Blue 4 blocks that, but then Red 5 can make territory two ways, and Blue is cooked. Blue 6 cuts off one of those ways and takes 10 squares. Red 7 takes territory, leaving Blue with the option to take 4 squares with A or 2 squares plus a prisoner at B.
But Herman upstaged me again (a pattern is emerging) with this solution. After Red 1 and Blue 2, Red 3 threatens to make territory at 4. Blue can only block with 4. Then Red 5 threatens to make territory at 6, and again Blue can only block by playing at 6. Then Red 7 closes the deal, able to make territory at both A and B.
Blue should block with 8 shown here. After that Red 9 is required or Red is prisoners. Blue 10 for 4 squares is optional. The result is 4 squares for Red, 3 squares for Red with an option for 4 more. This is a huge reversal, but Blue can do better.
Here Blue does the sensible thing and cuts Red off with Blue 2. Red 3 threatens to sneak under (and to make territory at 5, crucial), but Blue 4 cuts that off and takes 13 squares of territory. Then Red 5 takes 2 squares. After that everything is optional. Blue 6 takes 5 squares, Red 7 takes 1.